Engine run time to keep battery charged
On Tue, 5 Feb 2019 01:30:54 -0000 (UTC), arlen holder wrote:
> Let's assume it takes five to ten seconds to start it, at 500 amps, where
> the maximum _power _would be 10 seconds times 500 amps, which means you
> sucked out 5,000 Coulombs (i.e., 5000 amp seconds) if the math is right.
Ooops... Coulombs ... not power... (power would be via P=IV or I^2R but
not amp seconds)...
(I hacked that out in a minute on the run, so, please correct where I err.)
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